x^2+14x+28=0

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Solution for x^2+14x+28=0 equation:


Simplifying
x2 + 14x + 28 = 0

Reorder the terms:
28 + 14x + x2 = 0

Solving
28 + 14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-28' to each side of the equation.
28 + 14x + -28 + x2 = 0 + -28

Reorder the terms:
28 + -28 + 14x + x2 = 0 + -28

Combine like terms: 28 + -28 = 0
0 + 14x + x2 = 0 + -28
14x + x2 = 0 + -28

Combine like terms: 0 + -28 = -28
14x + x2 = -28

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -28 + 49

Reorder the terms:
49 + 14x + x2 = -28 + 49

Combine like terms: -28 + 49 = 21
49 + 14x + x2 = 21

Factor a perfect square on the left side:
(x + 7)(x + 7) = 21

Calculate the square root of the right side: 4.582575695

Break this problem into two subproblems by setting 
(x + 7) equal to 4.582575695 and -4.582575695.

Subproblem 1

x + 7 = 4.582575695 Simplifying x + 7 = 4.582575695 Reorder the terms: 7 + x = 4.582575695 Solving 7 + x = 4.582575695 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 4.582575695 + -7 Combine like terms: 7 + -7 = 0 0 + x = 4.582575695 + -7 x = 4.582575695 + -7 Combine like terms: 4.582575695 + -7 = -2.417424305 x = -2.417424305 Simplifying x = -2.417424305

Subproblem 2

x + 7 = -4.582575695 Simplifying x + 7 = -4.582575695 Reorder the terms: 7 + x = -4.582575695 Solving 7 + x = -4.582575695 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = -4.582575695 + -7 Combine like terms: 7 + -7 = 0 0 + x = -4.582575695 + -7 x = -4.582575695 + -7 Combine like terms: -4.582575695 + -7 = -11.582575695 x = -11.582575695 Simplifying x = -11.582575695

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-2.417424305, -11.582575695}

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